13442121433 has 4 divisors (see below), whose sum is σ = 14476130788. Its totient is φ = 12408112080.

The previous prime is 13442121397. The next prime is 13442121437. The reversal of 13442121433 is 33412124431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33412124431 = 7 ⋅4773160633.

It can be written as a sum of positive squares in 2 ways, for example, as 4285928089 + 9156193344 = 65467^2 + 95688^2 .

It is not a de Polignac number, because 13442121433 - 2⁹ = 13442120921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13442121437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 517004658 + ... + 517004683.

It is an arithmetic number, because the mean of its divisors is an integer number (3619032697).

Almost surely, 2^13442121433 is an apocalyptic number.

13442121433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13442121433 is a deficient number, since it is larger than the sum of its proper divisors (1034009355).

13442121433 is a wasteful number, since it uses less digits than its factorization.

13442121433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1034009354.

The product of its digits is 6912, while the sum is 28.

Adding to 13442121433 its reverse (33412124431), we get a palindrome (46854245864).

The spelling of 13442121433 in words is "thirteen billion, four hundred forty-two million, one hundred twenty-one thousand, four hundred thirty-three".