Base | Representation |
---|---|
bin | 11001000010011100… |
… | …00001000011001111 |
3 | 1021200210220202012120 |
4 | 30201032001003033 |
5 | 210012202134320 |
6 | 10101505304023 |
7 | 654053010261 |
oct | 144116010317 |
9 | 37623822176 |
10 | 13442224335 |
11 | 5778870111 |
12 | 2731935013 |
13 | 1362ba83c7 |
14 | 9173a1b31 |
15 | 53a1a6440 |
hex | 3213810cf |
13442224335 has 8 divisors (see below), whose sum is σ = 21507558960. Its totient is φ = 7169186304.
The previous prime is 13442224267. The next prime is 13442224337. The reversal of 13442224335 is 53342224431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13442224335 - 217 = 13442093263 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13442224296 and 13442224305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13442224337) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 448074130 + ... + 448074159.
It is an arithmetic number, because the mean of its divisors is an integer number (2688444870).
Almost surely, 213442224335 is an apocalyptic number.
13442224335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13442224335 is a deficient number, since it is larger than the sum of its proper divisors (8065334625).
13442224335 is an equidigital number, since it uses as much as digits as its factorization.
13442224335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 896148297.
The product of its digits is 69120, while the sum is 33.
Adding to 13442224335 its reverse (53342224431), we get a palindrome (66784448766).
The spelling of 13442224335 in words is "thirteen billion, four hundred forty-two million, two hundred twenty-four thousand, three hundred thirty-five".
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