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134423544053 is a prime number
BaseRepresentation
bin111110100110001000…
…1001000000011110101
3110211222012121120021202
41331030101020003311
54200244411402203
6141430415022245
712466066162151
oct1751421100365
9424865546252
10134423544053
115201064a267
122207620a985
13c8a348c116
146712b92061
15376b39d388
hex1f4c4480f5

134423544053 has 2 divisors, whose sum is σ = 134423544054. Its totient is φ = 134423544052.

The previous prime is 134423544043. The next prime is 134423544061. The reversal of 134423544053 is 350445324431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129950877169 + 4472666884 = 360487^2 + 66878^2 .

It is a cyclic number.

It is not a de Polignac number, because 134423544053 - 24 = 134423544037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134423543998 and 134423544016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134423544043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67211772026 + 67211772027.

It is an arithmetic number, because the mean of its divisors is an integer number (67211772027).

Almost surely, 2134423544053 is an apocalyptic number.

It is an amenable number.

134423544053 is a deficient number, since it is larger than the sum of its proper divisors (1).

134423544053 is an equidigital number, since it uses as much as digits as its factorization.

134423544053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 345600, while the sum is 38.

Adding to 134423544053 its reverse (350445324431), we get a palindrome (484868868484).

The spelling of 134423544053 in words is "one hundred thirty-four billion, four hundred twenty-three million, five hundred forty-four thousand, fifty-three".