Base | Representation |
---|---|
bin | 10011100011111010111… |
… | …101011011011011110111 |
3 | 11202111201102002122110010 |
4 | 103203322331123123313 |
5 | 134011000443003021 |
6 | 2505311352431303 |
7 | 166055345126502 |
oct | 23437275333367 |
9 | 4674642078403 |
10 | 1344240203511 |
11 | 4790a8606957 |
12 | 1986333a8533 |
13 | 999b8790a5a |
14 | 490c0d56139 |
15 | 24e77ccd976 |
hex | 138faf5b6f7 |
1344240203511 has 4 divisors (see below), whose sum is σ = 1792320271352. Its totient is φ = 896160135672.
The previous prime is 1344240203461. The next prime is 1344240203513. The reversal of 1344240203511 is 1153020424431.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1344240203511 - 29 = 1344240202999 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1344240203513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224040033916 + ... + 224040033921.
It is an arithmetic number, because the mean of its divisors is an integer number (448080067838).
Almost surely, 21344240203511 is an apocalyptic number.
1344240203511 is a deficient number, since it is larger than the sum of its proper divisors (448080067841).
1344240203511 is an equidigital number, since it uses as much as digits as its factorization.
1344240203511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 448080067840.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 1344240203511 its reverse (1153020424431), we get a palindrome (2497260627942).
The spelling of 1344240203511 in words is "one trillion, three hundred forty-four billion, two hundred forty million, two hundred three thousand, five hundred eleven".
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