Base | Representation |
---|---|
bin | 10011100011111100100… |
… | …000001100100100000011 |
3 | 11202111210012211001200122 |
4 | 103203330200030210003 |
5 | 134011024110013401 |
6 | 2505314115410455 |
7 | 166056111163451 |
oct | 23437440144403 |
9 | 4674705731618 |
10 | 1344266094851 |
11 | 479111190459 |
12 | 19863bbb3a2b |
13 | 999c0c57884 |
14 | 490c45759d1 |
15 | 24e7a1e521b |
hex | 138fc80c903 |
1344266094851 has 2 divisors, whose sum is σ = 1344266094852. Its totient is φ = 1344266094850.
The previous prime is 1344266094799. The next prime is 1344266094863. The reversal of 1344266094851 is 1584906624431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1344266094851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1344266094793 and 1344266094802.
It is not a weakly prime, because it can be changed into another prime (1344266090851) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672133047425 + 672133047426.
It is an arithmetic number, because the mean of its divisors is an integer number (672133047426).
Almost surely, 21344266094851 is an apocalyptic number.
1344266094851 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344266094851 is an equidigital number, since it uses as much as digits as its factorization.
1344266094851 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4976640, while the sum is 53.
The spelling of 1344266094851 in words is "one trillion, three hundred forty-four billion, two hundred sixty-six million, ninety-four thousand, eight hundred fifty-one".
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