Base | Representation |
---|---|
bin | 10011100011111100100… |
… | …000001100100011001111 |
3 | 11202111210012211001121201 |
4 | 103203330200030203033 |
5 | 134011024110013144 |
6 | 2505314115410331 |
7 | 166056111163345 |
oct | 23437440144317 |
9 | 4674705731551 |
10 | 1344266094799 |
11 | 479111190411 |
12 | 19863bbb39a7 |
13 | 999c0c57844 |
14 | 490c4575995 |
15 | 24e7a1e51d4 |
hex | 138fc80c8cf |
1344266094799 has 2 divisors, whose sum is σ = 1344266094800. Its totient is φ = 1344266094798.
The previous prime is 1344266094797. The next prime is 1344266094851. The reversal of 1344266094799 is 9974906624431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1344266094799 - 21 = 1344266094797 is a prime.
Together with 1344266094797, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 1344266094799.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344266094791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672133047399 + 672133047400.
It is an arithmetic number, because the mean of its divisors is an integer number (672133047400).
Almost surely, 21344266094799 is an apocalyptic number.
1344266094799 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344266094799 is an equidigital number, since it uses as much as digits as its factorization.
1344266094799 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 70543872, while the sum is 64.
The spelling of 1344266094799 in words is "one trillion, three hundred forty-four billion, two hundred sixty-six million, ninety-four thousand, seven hundred ninety-nine".
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