Base | Representation |
---|---|
bin | 111110100110010110… |
… | …1101010000010100111 |
3 | 110211222201200112211211 |
4 | 1331030231222002213 |
5 | 4200303320221041 |
6 | 141431243212251 |
7 | 12466216562356 |
oct | 1751455520247 |
9 | 424881615754 |
10 | 134431023271 |
11 | 52014898536 |
12 | 22078817087 |
13 | c8a4baa4ac |
14 | 6713b7b99d |
15 | 376bd79481 |
hex | 1f4cb6a0a7 |
134431023271 has 2 divisors, whose sum is σ = 134431023272. Its totient is φ = 134431023270.
The previous prime is 134431023269. The next prime is 134431023347. The reversal of 134431023271 is 172320134431.
It is a weak prime.
It is an emirp because it is prime and its reverse (172320134431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134431023271 - 21 = 134431023269 is a prime.
Together with 134431023269, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134431023211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67215511635 + 67215511636.
It is an arithmetic number, because the mean of its divisors is an integer number (67215511636).
Almost surely, 2134431023271 is an apocalyptic number.
134431023271 is a deficient number, since it is larger than the sum of its proper divisors (1).
134431023271 is an equidigital number, since it uses as much as digits as its factorization.
134431023271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
The spelling of 134431023271 in words is "one hundred thirty-four billion, four hundred thirty-one million, twenty-three thousand, two hundred seventy-one".
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