Base | Representation |
---|---|
bin | 11001000010100010… |
… | …11010010001110101 |
3 | 1021200212120221201212 |
4 | 30201101122101311 |
5 | 210012414122401 |
6 | 10101540331205 |
7 | 654063404324 |
oct | 144121322165 |
9 | 37625527655 |
10 | 13443114101 |
11 | 577931865a |
12 | 27320a3b05 |
13 | 136312a3b1 |
14 | 9175540bb |
15 | 53a2cedbb |
hex | 32145a475 |
13443114101 has 2 divisors, whose sum is σ = 13443114102. Its totient is φ = 13443114100.
The previous prime is 13443114049. The next prime is 13443114121. The reversal of 13443114101 is 10141134431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13173300625 + 269813476 = 114775^2 + 16426^2 .
It is an emirp because it is prime and its reverse (10141134431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13443114101 - 210 = 13443113077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13443114121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721557050 + 6721557051.
It is an arithmetic number, because the mean of its divisors is an integer number (6721557051).
Almost surely, 213443114101 is an apocalyptic number.
It is an amenable number.
13443114101 is a deficient number, since it is larger than the sum of its proper divisors (1).
13443114101 is an equidigital number, since it uses as much as digits as its factorization.
13443114101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 13443114101 its reverse (10141134431), we get a palindrome (23584248532).
The spelling of 13443114101 in words is "thirteen billion, four hundred forty-three million, one hundred fourteen thousand, one hundred one".
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