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1344321043321 is a prime number
BaseRepresentation
bin10011100011111111110…
…001110011101101111001
311202111221001012201211011
4103203333301303231321
5134011132141341241
62505323401233521
7166060346221204
oct23437761635571
94674831181734
101344321043321
1147913a201013
121986564928a1
13999cc456469
14490cb99a93b
1524e7ee4b281
hex138ffc73b79

1344321043321 has 2 divisors, whose sum is σ = 1344321043322. Its totient is φ = 1344321043320.

The previous prime is 1344321043319. The next prime is 1344321043349. The reversal of 1344321043321 is 1233401234431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 690875153721 + 653445889600 = 831189^2 + 808360^2 .

It is an emirp because it is prime and its reverse (1233401234431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1344321043321 - 21 = 1344321043319 is a prime.

Together with 1344321043319, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1344321043721) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672160521660 + 672160521661.

It is an arithmetic number, because the mean of its divisors is an integer number (672160521661).

Almost surely, 21344321043321 is an apocalyptic number.

It is an amenable number.

1344321043321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344321043321 is an equidigital number, since it uses as much as digits as its factorization.

1344321043321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1344321043321 its reverse (1233401234431), we get a palindrome (2577722277752).

The spelling of 1344321043321 in words is "one trillion, three hundred forty-four billion, three hundred twenty-one million, forty-three thousand, three hundred twenty-one".