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1344321043319 is a prime number
BaseRepresentation
bin10011100011111111110…
…001110011101101110111
311202111221001012201211002
4103203333301303231313
5134011132141341234
62505323401233515
7166060346221202
oct23437761635567
94674831181732
101344321043319
1147913a201011
1219865649289b
13999cc456467
14490cb99a939
1524e7ee4b27e
hex138ffc73b77

1344321043319 has 2 divisors, whose sum is σ = 1344321043320. Its totient is φ = 1344321043318.

The previous prime is 1344321043291. The next prime is 1344321043321. The reversal of 1344321043319 is 9133401234431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1344321043319 is a prime.

It is a super-2 number, since 2×13443210433192 (a number of 25 digits) contains 22 as substring.

Together with 1344321043321, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1344321043349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672160521659 + 672160521660.

It is an arithmetic number, because the mean of its divisors is an integer number (672160521660).

Almost surely, 21344321043319 is an apocalyptic number.

1344321043319 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344321043319 is an equidigital number, since it uses as much as digits as its factorization.

1344321043319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 93312, while the sum is 38.

The spelling of 1344321043319 in words is "one trillion, three hundred forty-four billion, three hundred twenty-one million, forty-three thousand, three hundred nineteen".