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134432120622403 is a prime number
BaseRepresentation
bin11110100100001111101010…
…110010111100110101000011
3122121222120210121220001010101
4132210033222302330311003
5120110013440334404103
61153525132540343231
740213254161332222
oct3644175262746503
9577876717801111
10134432120622403
113991a3844a921a
12130b1a19244b17
135a01b825126a6
14252a799602cb9
151081d4bd13a1d
hex7a43eacbcd43

134432120622403 has 2 divisors, whose sum is σ = 134432120622404. Its totient is φ = 134432120622402.

The previous prime is 134432120622379. The next prime is 134432120622427. The reversal of 134432120622403 is 304226021234431.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (134432120622379) and next prime (134432120622427).

It is a cyclic number.

It is not a de Polignac number, because 134432120622403 - 221 = 134432118525251 is a prime.

It is a super-2 number, since 2×1344321206224032 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134432120622473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67216060311201 + 67216060311202.

It is an arithmetic number, because the mean of its divisors is an integer number (67216060311202).

Almost surely, 2134432120622403 is an apocalyptic number.

134432120622403 is a deficient number, since it is larger than the sum of its proper divisors (1).

134432120622403 is an equidigital number, since it uses as much as digits as its factorization.

134432120622403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 165888, while the sum is 37.

Adding to 134432120622403 its reverse (304226021234431), we get a palindrome (438658141856834).

The spelling of 134432120622403 in words is "one hundred thirty-four trillion, four hundred thirty-two billion, one hundred twenty million, six hundred twenty-two thousand, four hundred three".