Base | Representation |
---|---|
bin | 10011100100000000011… |
… | …001010100001101100011 |
3 | 11202111221202200220120011 |
4 | 103210000121110031203 |
5 | 134011142314300120 |
6 | 2505324411225351 |
7 | 166060533234541 |
oct | 23440031241543 |
9 | 4674852626504 |
10 | 1344331400035 |
11 | 479145035188 |
12 | 198659a48257 |
13 | 99a016414b0 |
14 | 490cd0d4d91 |
15 | 24e80ce4c5a |
hex | 13900654363 |
1344331400035 has 32 divisors (see below), whose sum is σ = 1759533834240. Its totient is φ = 980029784448.
The previous prime is 1344331400003. The next prime is 1344331400039. The reversal of 1344331400035 is 5300041334431.
It is not a de Polignac number, because 1344331400035 - 25 = 1344331400003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1344331400039) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 47243182 + ... + 47271628.
It is an arithmetic number, because the mean of its divisors is an integer number (54985432320).
Almost surely, 21344331400035 is an apocalyptic number.
1344331400035 is a deficient number, since it is larger than the sum of its proper divisors (415202434205).
1344331400035 is a wasteful number, since it uses less digits than its factorization.
1344331400035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37747.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 1344331400035 its reverse (5300041334431), we get a palindrome (6644372734466).
The spelling of 1344331400035 in words is "one trillion, three hundred forty-four billion, three hundred thirty-one million, four hundred thousand, thirty-five".
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