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13443320003 = 75717758679
BaseRepresentation
bin11001000010100100…
…01100100011000011
31021200212222102011212
430201102030203003
5210012442220003
610101545000335
7654065222531
oct144122144303
937625872155
1013443320003
115779449323
1227321830ab
1313631a0029
149175a9151
1553a320dd8
hex32148c8c3

13443320003 has 4 divisors (see below), whose sum is σ = 13461079440. Its totient is φ = 13425560568.

The previous prime is 13443319997. The next prime is 13443320041. The reversal of 13443320003 is 30002334431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30002334431 = 40917333741.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13443320003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13443320603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8878583 + ... + 8880096.

It is an arithmetic number, because the mean of its divisors is an integer number (3365269860).

Almost surely, 213443320003 is an apocalyptic number.

13443320003 is a deficient number, since it is larger than the sum of its proper divisors (17759437).

13443320003 is an equidigital number, since it uses as much as digits as its factorization.

13443320003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17759436.

The product of its (nonzero) digits is 2592, while the sum is 23.

Adding to 13443320003 its reverse (30002334431), we get a palindrome (43445654434).

The spelling of 13443320003 in words is "thirteen billion, four hundred forty-three million, three hundred twenty thousand, three".

Divisors: 1 757 17758679 13443320003