Base | Representation |
---|---|
bin | 10011100100000000111… |
… | …010001101101111101101 |
3 | 11202111222100221001211102 |
4 | 103210000322031233231 |
5 | 134011202021234201 |
6 | 2505325320132445 |
7 | 166060666444301 |
oct | 23440072155755 |
9 | 4674870831742 |
10 | 1344340024301 |
11 | 47914999577a |
12 | 198660907125 |
13 | 99a03370b01 |
14 | 490d02dbd01 |
15 | 24e8194a26b |
hex | 13900e8dbed |
1344340024301 has 2 divisors, whose sum is σ = 1344340024302. Its totient is φ = 1344340024300.
The previous prime is 1344340024271. The next prime is 1344340024381. The reversal of 1344340024301 is 1034200434431.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 725205528100 + 619134496201 = 851590^2 + 786851^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1344340024301 is a prime.
It is a super-2 number, since 2×13443400243012 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344340024381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672170012150 + 672170012151.
It is an arithmetic number, because the mean of its divisors is an integer number (672170012151).
Almost surely, 21344340024301 is an apocalyptic number.
It is an amenable number.
1344340024301 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344340024301 is an equidigital number, since it uses as much as digits as its factorization.
1344340024301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 1344340024301 its reverse (1034200434431), we get a palindrome (2378540458732).
The spelling of 1344340024301 in words is "one trillion, three hundred forty-four billion, three hundred forty million, twenty-four thousand, three hundred one".
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