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134434118907797 is a prime number
BaseRepresentation
bin11110100100010001100001…
…111001110011011110010101
3122121222202221220000110100112
4132210101201321303132111
5120110032033420022142
61153530103122452405
740213354534433162
oct3644214171633625
9577882856013315
10134434118907797
113992020a484655
12130b2296504105
135a02110509497
14252a908b73069
151081e17488382
hex7a4461e73795

134434118907797 has 2 divisors, whose sum is σ = 134434118907798. Its totient is φ = 134434118907796.

The previous prime is 134434118907731. The next prime is 134434118907799. The reversal of 134434118907797 is 797709811434431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107059394996401 + 27374723911396 = 10346951^2 + 5232086^2 .

It is a cyclic number.

It is not a de Polignac number, because 134434118907797 - 28 = 134434118907541 is a prime.

Together with 134434118907799, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134434118907799) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67217059453898 + 67217059453899.

It is an arithmetic number, because the mean of its divisors is an integer number (67217059453899).

Almost surely, 2134434118907797 is an apocalyptic number.

It is an amenable number.

134434118907797 is a deficient number, since it is larger than the sum of its proper divisors (1).

134434118907797 is an equidigital number, since it uses as much as digits as its factorization.

134434118907797 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 128024064, while the sum is 68.

The spelling of 134434118907797 in words is "one hundred thirty-four trillion, four hundred thirty-four billion, one hundred eighteen million, nine hundred seven thousand, seven hundred ninety-seven".