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1344410979869 is a prime number
BaseRepresentation
bin10011100100000101001…
…000111000111000011101
311202112011022102222120102
4103210011020320320131
5134011323202323434
62505340333030445
7166062520530656
oct23440510707035
94675138388512
101344410979869
11479185a49741
12198680625425
1399a14c85559
14490d98cc52d
1524e87cb407e
hex13905238e1d

1344410979869 has 2 divisors, whose sum is σ = 1344410979870. Its totient is φ = 1344410979868.

The previous prime is 1344410979833. The next prime is 1344410979871. The reversal of 1344410979869 is 9689790144431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1294486440025 + 49924539844 = 1137755^2 + 223438^2 .

It is a cyclic number.

It is not a de Polignac number, because 1344410979869 - 228 = 1344142544413 is a prime.

It is a super-2 number, since 2×13444109798692 (a number of 25 digits) contains 22 as substring.

Together with 1344410979871, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1344410979469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672205489934 + 672205489935.

It is an arithmetic number, because the mean of its divisors is an integer number (672205489935).

Almost surely, 21344410979869 is an apocalyptic number.

It is an amenable number.

1344410979869 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344410979869 is an equidigital number, since it uses as much as digits as its factorization.

1344410979869 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 47029248, while the sum is 65.

The spelling of 1344410979869 in words is "one trillion, three hundred forty-four billion, four hundred ten million, nine hundred seventy-nine thousand, eight hundred sixty-nine".