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13444121201 = 71920588743
BaseRepresentation
bin11001000010101010…
…10000001001110001
31021200221111010012212
430201111100021301
5210013143334301
610102014101505
7654105100430
oct144125201161
937627433185
1013444121201
115779946275
1227324aa895
1313633c0904
14917737117
1553a42d4bb
hex321550271

13444121201 has 4 divisors (see below), whose sum is σ = 15364709952. Its totient is φ = 11523532452.

The previous prime is 13444121177. The next prime is 13444121219. The reversal of 13444121201 is 10212144431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13444121201 - 218 = 13443859057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13444121501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 960294365 + ... + 960294378.

It is an arithmetic number, because the mean of its divisors is an integer number (3841177488).

Almost surely, 213444121201 is an apocalyptic number.

It is an amenable number.

13444121201 is a deficient number, since it is larger than the sum of its proper divisors (1920588751).

13444121201 is an equidigital number, since it uses as much as digits as its factorization.

13444121201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1920588750.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 13444121201 its reverse (10212144431), we get a palindrome (23656265632).

The spelling of 13444121201 in words is "thirteen billion, four hundred forty-four million, one hundred twenty-one thousand, two hundred one".

Divisors: 1 7 1920588743 13444121201