Base | Representation |
---|---|
bin | 11110100100011001010001… |
… | …101001011000011110101111 |
3 | 122122000120102112021200222121 |
4 | 132210121101221120132233 |
5 | 120110201102120231223 |
6 | 1153534000313053411 |
7 | 40214100616425025 |
oct | 3644312151303657 |
9 | 578016375250877 |
10 | 134442436102063 |
11 | 399237982aa821 |
12 | 130b3a179b7267 |
13 | 5a02b3768a6cb |
14 | 252b097608715 |
15 | 108225273c15d |
hex | 7a4651a587af |
134442436102063 has 4 divisors (see below), whose sum is σ = 142350814696320. Its totient is φ = 126534057507808.
The previous prime is 134442436102061. The next prime is 134442436102087. The reversal of 134442436102063 is 360201634244431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134442436102063 - 21 = 134442436102061 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134442436102061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3954189297103 + ... + 3954189297136.
It is an arithmetic number, because the mean of its divisors is an integer number (35587703674080).
Almost surely, 2134442436102063 is an apocalyptic number.
134442436102063 is a deficient number, since it is larger than the sum of its proper divisors (7908378594257).
134442436102063 is an equidigital number, since it uses as much as digits as its factorization.
134442436102063 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7908378594256.
The product of its (nonzero) digits is 995328, while the sum is 43.
The spelling of 134442436102063 in words is "one hundred thirty-four trillion, four hundred forty-two billion, four hundred thirty-six million, one hundred two thousand, sixty-three".
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