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13444251253050 = 235289628341687
BaseRepresentation
bin1100001110100011101111…
…0100011111100100111010
31202121020221222121110121110
43003220323310133210322
53230232311310044200
644332112002421150
72555213036061102
oct303507364374472
952536858543543
1013444251253050
114313747383502
1216117046617b6
13766a3105b557
143469c3230202
15184ab0dbcb50
hexc3a3bd1f93a

13444251253050 has 24 divisors (see below), whose sum is σ = 33341743107936. Its totient is φ = 3585133667440.

The previous prime is 13444251253033. The next prime is 13444251253063. The reversal of 13444251253050 is 5035215244431.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 44814170694 + ... + 44814170993.

It is an arithmetic number, because the mean of its divisors is an integer number (1389239296164).

Almost surely, 213444251253050 is an apocalyptic number.

13444251253050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13444251253050 is an abundant number, since it is smaller than the sum of its proper divisors (19897491854886).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13444251253050 is a wasteful number, since it uses less digits than its factorization.

13444251253050 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 89628341702 (or 89628341697 counting only the distinct ones).

The product of its (nonzero) digits is 288000, while the sum is 39.

Adding to 13444251253050 its reverse (5035215244431), we get a palindrome (18479466497481).

The spelling of 13444251253050 in words is "thirteen trillion, four hundred forty-four billion, two hundred fifty-one million, two hundred fifty-three thousand, fifty".

Divisors: 1 2 3 5 6 10 15 25 30 50 75 150 89628341687 179256683374 268885025061 448141708435 537770050122 896283416870 1344425125305 2240708542175 2688850250610 4481417084350 6722125626525 13444251253050