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134443891061 is a prime number
BaseRepresentation
bin111110100110101111…
…0101111100101110101
3110212000121220022010122
41331031132233211311
54200320114003221
6141432423101325
712466434134654
oct1751536574565
9425017808118
10134443891061
1152021087277
1222080ba1845
13c8a776447c
14671576b19b
15376d06beab
hex1f4d7af975

134443891061 has 2 divisors, whose sum is σ = 134443891062. Its totient is φ = 134443891060.

The previous prime is 134443891051. The next prime is 134443891063. The reversal of 134443891061 is 160198344431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117093996100 + 17349894961 = 342190^2 + 131719^2 .

It is an emirp because it is prime and its reverse (160198344431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134443891061 - 210 = 134443890037 is a prime.

Together with 134443891063, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134443891063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67221945530 + 67221945531.

It is an arithmetic number, because the mean of its divisors is an integer number (67221945531).

Almost surely, 2134443891061 is an apocalyptic number.

It is an amenable number.

134443891061 is a deficient number, since it is larger than the sum of its proper divisors (1).

134443891061 is an equidigital number, since it uses as much as digits as its factorization.

134443891061 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 248832, while the sum is 44.

The spelling of 134443891061 in words is "one hundred thirty-four billion, four hundred forty-three million, eight hundred ninety-one thousand, sixty-one".