Base | Representation |
---|---|
bin | 11110100100100000010110… |
… | …111100001100111011000011 |
3 | 122122001022001112110100112202 |
4 | 132210200112330030323003 |
5 | 120110312141011124212 |
6 | 1153541255102543415 |
7 | 40214460233110262 |
oct | 3644402674147303 |
9 | 578038045410482 |
10 | 134450041114307 |
11 | 39926a40116006 |
12 | 130b539a897b6b |
13 | 5a0377a125759 |
14 | 252b5b96545d9 |
15 | 108254a2140c2 |
hex | 7a4816f0cec3 |
134450041114307 has 2 divisors, whose sum is σ = 134450041114308. Its totient is φ = 134450041114306.
The previous prime is 134450041114303. The next prime is 134450041114387. The reversal of 134450041114307 is 703411140054431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134450041114307 - 22 = 134450041114303 is a prime.
It is not a weakly prime, because it can be changed into another prime (134450041114303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67225020557153 + 67225020557154.
It is an arithmetic number, because the mean of its divisors is an integer number (67225020557154).
Almost surely, 2134450041114307 is an apocalyptic number.
134450041114307 is a deficient number, since it is larger than the sum of its proper divisors (1).
134450041114307 is an equidigital number, since it uses as much as digits as its factorization.
134450041114307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 38.
Adding to 134450041114307 its reverse (703411140054431), we get a palindrome (837861181168738).
The spelling of 134450041114307 in words is "one hundred thirty-four trillion, four hundred fifty billion, forty-one million, one hundred fourteen thousand, three hundred seven".
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