Base | Representation |
---|---|
bin | 11110100100100000010110… |
… | …111100001100111100010011 |
3 | 122122001022001112110100122201 |
4 | 132210200112330030330103 |
5 | 120110312141011130022 |
6 | 1153541255102544031 |
7 | 40214460233110435 |
oct | 3644402674147423 |
9 | 578038045410581 |
10 | 134450041114387 |
11 | 39926a40116079 |
12 | 130b539a898017 |
13 | 5a0377a1257bb |
14 | 252b5b9654655 |
15 | 108254a214127 |
hex | 7a4816f0cf13 |
134450041114387 has 2 divisors, whose sum is σ = 134450041114388. Its totient is φ = 134450041114386.
The previous prime is 134450041114307. The next prime is 134450041114457. The reversal of 134450041114387 is 783411140054431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134450041114387 - 239 = 133900285300499 is a prime.
It is not a weakly prime, because it can be changed into another prime (134450041114307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67225020557193 + 67225020557194.
It is an arithmetic number, because the mean of its divisors is an integer number (67225020557194).
Almost surely, 2134450041114387 is an apocalyptic number.
134450041114387 is a deficient number, since it is larger than the sum of its proper divisors (1).
134450041114387 is an equidigital number, since it uses as much as digits as its factorization.
134450041114387 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 645120, while the sum is 46.
The spelling of 134450041114387 in words is "one hundred thirty-four trillion, four hundred fifty billion, forty-one million, one hundred fourteen thousand, three hundred eighty-seven".
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