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13445115504055 = 52689023100811
BaseRepresentation
bin1100001110100110111101…
…0101010110010110110111
31202121100012012211222002221
43003221233111112112313
53230241044032112210
644332333434343211
72555243332065244
oct303515725262667
952540165758087
1013445115504055
114314050209034
121611905b8ab07
13766b3b119291
14346a65d225cb
15184b11bd71da
hexc3a6f5565b7

13445115504055 has 4 divisors (see below), whose sum is σ = 16134138604872. Its totient is φ = 10756092403240.

The previous prime is 13445115504031. The next prime is 13445115504091. The reversal of 13445115504055 is 55040551154431.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13445115504055 - 225 = 13445081949623 is a prime.

It is a super-2 number, since 2×134451155040552 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1344511550401 + ... + 1344511550410.

It is an arithmetic number, because the mean of its divisors is an integer number (4033534651218).

Almost surely, 213445115504055 is an apocalyptic number.

13445115504055 is a deficient number, since it is larger than the sum of its proper divisors (2689023100817).

13445115504055 is an equidigital number, since it uses as much as digits as its factorization.

13445115504055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2689023100816.

The product of its (nonzero) digits is 600000, while the sum is 43.

Adding to 13445115504055 its reverse (55040551154431), we get a palindrome (68485666658486).

The spelling of 13445115504055 in words is "thirteen trillion, four hundred forty-five billion, one hundred fifteen million, five hundred four thousand, fifty-five".

Divisors: 1 5 2689023100811 13445115504055