Base | Representation |
---|---|
bin | 1100001110100110111101… |
… | …0101010110010110110111 |
3 | 1202121100012012211222002221 |
4 | 3003221233111112112313 |
5 | 3230241044032112210 |
6 | 44332333434343211 |
7 | 2555243332065244 |
oct | 303515725262667 |
9 | 52540165758087 |
10 | 13445115504055 |
11 | 4314050209034 |
12 | 1611905b8ab07 |
13 | 766b3b119291 |
14 | 346a65d225cb |
15 | 184b11bd71da |
hex | c3a6f5565b7 |
13445115504055 has 4 divisors (see below), whose sum is σ = 16134138604872. Its totient is φ = 10756092403240.
The previous prime is 13445115504031. The next prime is 13445115504091. The reversal of 13445115504055 is 55040551154431.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13445115504055 - 225 = 13445081949623 is a prime.
It is a super-2 number, since 2×134451155040552 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1344511550401 + ... + 1344511550410.
It is an arithmetic number, because the mean of its divisors is an integer number (4033534651218).
Almost surely, 213445115504055 is an apocalyptic number.
13445115504055 is a deficient number, since it is larger than the sum of its proper divisors (2689023100817).
13445115504055 is an equidigital number, since it uses as much as digits as its factorization.
13445115504055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2689023100816.
The product of its (nonzero) digits is 600000, while the sum is 43.
Adding to 13445115504055 its reverse (55040551154431), we get a palindrome (68485666658486).
The spelling of 13445115504055 in words is "thirteen trillion, four hundred forty-five billion, one hundred fifteen million, five hundred four thousand, fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •