Search a number
-
+
1344613204217 is a prime number
BaseRepresentation
bin10011100100010001001…
…100010100000011111001
311202112200101222001020002
4103210101030110003321
5134012231440013332
62505412355242345
7166100524441223
oct23442114240371
94675611861202
101344613204217
1147927a1108a8
121987182a93b5
1399a47b3b12a
14491186cd413
1524e9a90c562
hex139113140f9

1344613204217 has 2 divisors, whose sum is σ = 1344613204218. Its totient is φ = 1344613204216.

The previous prime is 1344613204199. The next prime is 1344613204219. The reversal of 1344613204217 is 7124023164431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1077919456441 + 266693747776 = 1038229^2 + 516424^2 .

It is a cyclic number.

It is not a de Polignac number, because 1344613204217 - 214 = 1344613187833 is a prime.

Together with 1344613204219, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1344613204219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672306602108 + 672306602109.

It is an arithmetic number, because the mean of its divisors is an integer number (672306602109).

Almost surely, 21344613204217 is an apocalyptic number.

It is an amenable number.

1344613204217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344613204217 is an equidigital number, since it uses as much as digits as its factorization.

1344613204217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96768, while the sum is 38.

Adding to 1344613204217 its reverse (7124023164431), we get a palindrome (8468636368648).

The spelling of 1344613204217 in words is "one trillion, three hundred forty-four billion, six hundred thirteen million, two hundred four thousand, two hundred seventeen".