Base | Representation |
---|---|
bin | 10011100100010111001… |
… | …111010011000011110111 |
3 | 11202112221110212000110122 |
4 | 103210113033103003313 |
5 | 134012433422243342 |
6 | 2505430421442155 |
7 | 166103165634122 |
oct | 23442717230367 |
9 | 4675843760418 |
10 | 1344714649847 |
11 | 4793213aa468 |
12 | 19874627035b |
13 | 99a62b6992a |
14 | 49127d793b9 |
15 | 24ea479a4d2 |
hex | 139173d30f7 |
1344714649847 has 2 divisors, whose sum is σ = 1344714649848. Its totient is φ = 1344714649846.
The previous prime is 1344714649813. The next prime is 1344714649913. The reversal of 1344714649847 is 7489464174431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1344714649847 - 214 = 1344714633463 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1344714649847.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344714649247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672357324923 + 672357324924.
It is an arithmetic number, because the mean of its divisors is an integer number (672357324924).
Almost surely, 21344714649847 is an apocalyptic number.
1344714649847 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344714649847 is an equidigital number, since it uses as much as digits as its factorization.
1344714649847 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 65028096, while the sum is 62.
The spelling of 1344714649847 in words is "one trillion, three hundred forty-four billion, seven hundred fourteen million, six hundred forty-nine thousand, eight hundred forty-seven".
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