Base | Representation |
---|---|
bin | 1100001110111001010110… |
… | …0001010110010111001111 |
3 | 1202121210221012010211022011 |
4 | 3003232111201112113033 |
5 | 3230331201043320221 |
6 | 44334511310402051 |
7 | 2555506543306345 |
oct | 303562541262717 |
9 | 52553835124264 |
10 | 13450051151311 |
11 | 4316153261955 |
12 | 1612862b00327 |
13 | 767446835908 |
14 | 346db3631995 |
15 | 184d0017b1e1 |
hex | c3b958565cf |
13450051151311 has 4 divisors (see below), whose sum is σ = 13450513969872. Its totient is φ = 13449588332752.
The previous prime is 13450051151287. The next prime is 13450051151401. The reversal of 13450051151311 is 11315115005431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13450051151311 - 29 = 13450051150799 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13450051151711) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231365686 + ... + 231423811.
It is an arithmetic number, because the mean of its divisors is an integer number (3362628492468).
Almost surely, 213450051151311 is an apocalyptic number.
13450051151311 is a deficient number, since it is larger than the sum of its proper divisors (462818561).
13450051151311 is an equidigital number, since it uses as much as digits as its factorization.
13450051151311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 462818560.
The product of its (nonzero) digits is 4500, while the sum is 31.
Adding to 13450051151311 its reverse (11315115005431), we get a palindrome (24765166156742).
The spelling of 13450051151311 in words is "thirteen trillion, four hundred fifty billion, fifty-one million, one hundred fifty-one thousand, three hundred eleven".
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