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134500918679 is a prime number
BaseRepresentation
bin111110101000011100…
…0010010010110010111
3110212011121012121022122
41331100320102112113
54200424213344204
6141442221250155
712501025642151
oct1752070222627
9425147177278
10134500918679
1152050297a36
122209810395b
13c8b651051a
14671d173ad1
1537730840be
hex1f50e12597

134500918679 has 2 divisors, whose sum is σ = 134500918680. Its totient is φ = 134500918678.

The previous prime is 134500918649. The next prime is 134500918681. The reversal of 134500918679 is 976819005431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134500918679 is a prime.

It is a super-2 number, since 2×1345009186792 (a number of 23 digits) contains 22 as substring.

Together with 134500918681, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134500918679.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134500918609) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67250459339 + 67250459340.

It is an arithmetic number, because the mean of its divisors is an integer number (67250459340).

Almost surely, 2134500918679 is an apocalyptic number.

134500918679 is a deficient number, since it is larger than the sum of its proper divisors (1).

134500918679 is an equidigital number, since it uses as much as digits as its factorization.

134500918679 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1632960, while the sum is 53.

The spelling of 134500918679 in words is "one hundred thirty-four billion, five hundred million, nine hundred eighteen thousand, six hundred seventy-nine".