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134502161066503 is a prime number
BaseRepresentation
bin11110100101010000111001…
…100010000010101000000111
3122122020021120212100020212121
4132211100321202002220013
5120112140411213112003
61154021234554230411
740221313636306546
oct3645207142025007
9578207525306777
10134502161066503
113994705650456a
1213103505725407
135a0866514aa59
14252dd2174615d
151083a9ac62cbd
hex7a5439882a07

134502161066503 has 2 divisors, whose sum is σ = 134502161066504. Its totient is φ = 134502161066502.

The previous prime is 134502161066501. The next prime is 134502161066513. The reversal of 134502161066503 is 305660161205431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 134502161066503 - 21 = 134502161066501 is a prime.

Together with 134502161066501, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 134502161066503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134502161066501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67251080533251 + 67251080533252.

It is an arithmetic number, because the mean of its divisors is an integer number (67251080533252).

Almost surely, 2134502161066503 is an apocalyptic number.

134502161066503 is a deficient number, since it is larger than the sum of its proper divisors (1).

134502161066503 is an equidigital number, since it uses as much as digits as its factorization.

134502161066503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 388800, while the sum is 43.

The spelling of 134502161066503 in words is "one hundred thirty-four trillion, five hundred two billion, one hundred sixty-one million, sixty-six thousand, five hundred three".