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1345034425381 is a prime number
BaseRepresentation
bin10011100100101010010…
…011001001010000100101
311202120202202120022000221
4103210222103021100211
5134014112303103011
62505522243404341
7166114130656243
oct23445223112045
94676682508027
101345034425381
11479475960569
121988153836b1
1399ab419c91a
1449158619793
1524ec28b3971
hex1392a4c9425

1345034425381 has 2 divisors, whose sum is σ = 1345034425382. Its totient is φ = 1345034425380.

The previous prime is 1345034425349. The next prime is 1345034425433. The reversal of 1345034425381 is 1835244305431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 905239976481 + 439794448900 = 951441^2 + 663170^2 .

It is a cyclic number.

It is not a de Polignac number, because 1345034425381 - 25 = 1345034425349 is a prime.

It is a super-2 number, since 2×13450344253812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1345034425081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672517212690 + 672517212691.

It is an arithmetic number, because the mean of its divisors is an integer number (672517212691).

Almost surely, 21345034425381 is an apocalyptic number.

It is an amenable number.

1345034425381 is a deficient number, since it is larger than the sum of its proper divisors (1).

1345034425381 is an equidigital number, since it uses as much as digits as its factorization.

1345034425381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 43.

The spelling of 1345034425381 in words is "one trillion, three hundred forty-five billion, thirty-four million, four hundred twenty-five thousand, three hundred eighty-one".