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13450425473101 is a prime number
BaseRepresentation
bin1100001110111010101111…
…0101010001100001001101
31202121211220021111100021011
43003232223311101201031
53230332432410114401
644335012401405221
72555522040062461
oct303565365214115
952554807440234
1013450425473101
114316325589401
121612948339811
137674a62563b6
1434700b2304a1
15184d22e6b451
hexc3babd5184d

13450425473101 has 2 divisors, whose sum is σ = 13450425473102. Its totient is φ = 13450425473100.

The previous prime is 13450425473083. The next prime is 13450425473117. The reversal of 13450425473101 is 10137452405431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10607391096201 + 2843034376900 = 3256899^2 + 1686130^2 .

It is a cyclic number.

It is not a de Polignac number, because 13450425473101 - 223 = 13450417084493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13450425473141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6725212736550 + 6725212736551.

It is an arithmetic number, because the mean of its divisors is an integer number (6725212736551).

Almost surely, 213450425473101 is an apocalyptic number.

It is an amenable number.

13450425473101 is a deficient number, since it is larger than the sum of its proper divisors (1).

13450425473101 is an equidigital number, since it uses as much as digits as its factorization.

13450425473101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 201600, while the sum is 40.

Adding to 13450425473101 its reverse (10137452405431), we get a palindrome (23587877878532).

The spelling of 13450425473101 in words is "thirteen trillion, four hundred fifty billion, four hundred twenty-five million, four hundred seventy-three thousand, one hundred one".