Base | Representation |
---|---|
bin | 11001000011011111… |
… | …11111100101011111 |
3 | 1021201102200021011121 |
4 | 30201233333211133 |
5 | 210021442144411 |
6 | 10102424231411 |
7 | 654221505016 |
oct | 144157774537 |
9 | 37642607147 |
10 | 13451131231 |
11 | 57828a3a8a |
12 | 273490b567 |
13 | 13649a6565 |
14 | 91863da7d |
15 | 53ad65571 |
hex | 321bff95f |
13451131231 has 2 divisors, whose sum is σ = 13451131232. Its totient is φ = 13451131230.
The previous prime is 13451131223. The next prime is 13451131283. The reversal of 13451131231 is 13213115431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13451131231 - 23 = 13451131223 is a prime.
It is a super-2 number, since 2×134511312312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13451131196 and 13451131205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13451131531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6725565615 + 6725565616.
It is an arithmetic number, because the mean of its divisors is an integer number (6725565616).
Almost surely, 213451131231 is an apocalyptic number.
13451131231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13451131231 is an equidigital number, since it uses as much as digits as its factorization.
13451131231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1080, while the sum is 25.
Adding to 13451131231 its reverse (13213115431), we get a palindrome (26664246662).
The spelling of 13451131231 in words is "thirteen billion, four hundred fifty-one million, one hundred thirty-one thousand, two hundred thirty-one".
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