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13451454031 is a prime number
BaseRepresentation
bin11001000011100010…
…01110011001001111
31021201110021122222011
430201301032121033
5210022033012111
610102435202051
7654224321101
oct144161163117
937643248864
1013451454031
115782aa4564
122734a46327
131364a8a472
149186c5571
1553adcb021
hex321c4e64f

13451454031 has 2 divisors, whose sum is σ = 13451454032. Its totient is φ = 13451454030.

The previous prime is 13451453993. The next prime is 13451454077. The reversal of 13451454031 is 13045415431.

13451454031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13451454031 - 231 = 11303970383 is a prime.

It is a super-2 number, since 2×134514540312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13451453984 and 13451454002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13451452031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6725727015 + 6725727016.

It is an arithmetic number, because the mean of its divisors is an integer number (6725727016).

Almost surely, 213451454031 is an apocalyptic number.

13451454031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13451454031 is an equidigital number, since it uses as much as digits as its factorization.

13451454031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 13451454031 its reverse (13045415431), we get a palindrome (26496869462).

The spelling of 13451454031 in words is "thirteen billion, four hundred fifty-one million, four hundred fifty-four thousand, thirty-one".