Base | Representation |
---|---|
bin | 10011100100110001011… |
… | …000101111000000100011 |
3 | 11202121002001022100012110 |
4 | 103210301120233000203 |
5 | 134014333223044420 |
6 | 2505542132130403 |
7 | 166120103442450 |
oct | 23446130570043 |
9 | 4677061270173 |
10 | 1345153331235 |
11 | 479526a9526a |
12 | 198849166a03 |
13 | 99b02a0280c |
14 | 4916a32c827 |
15 | 24ecd04eee0 |
hex | 1393162f023 |
1345153331235 has 128 divisors (see below), whose sum is σ = 2630683754496. Its totient is φ = 573533199360.
The previous prime is 1345153331209. The next prime is 1345153331261. The reversal of 1345153331235 is 5321333515431.
It is an interprime number because it is at equal distance from previous prime (1345153331209) and next prime (1345153331261).
It is not a de Polignac number, because 1345153331235 - 217 = 1345153200163 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1345153331193 and 1345153331202.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 342886984 + ... + 342890906.
It is an arithmetic number, because the mean of its divisors is an integer number (20552216832).
Almost surely, 21345153331235 is an apocalyptic number.
1345153331235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1345153331235 is a deficient number, since it is larger than the sum of its proper divisors (1285530423261).
1345153331235 is a wasteful number, since it uses less digits than its factorization.
1345153331235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7465.
The product of its digits is 243000, while the sum is 39.
Adding to 1345153331235 its reverse (5321333515431), we get a palindrome (6666486846666).
The spelling of 1345153331235 in words is "one trillion, three hundred forty-five billion, one hundred fifty-three million, three hundred thirty-one thousand, two hundred thirty-five".
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