1345311340031 has 4 divisors (see below), whose sum is σ = 1388708480064. Its totient is φ = 1301914200000.

The previous prime is 1345311340001. The next prime is 1345311340063. The reversal of 1345311340031 is 1300431135431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1345311340031 is a prime.

It is a super-2 number, since 2×1345311340031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1345311339976 and 1345311340003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1345311340001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21698569970 + ... + 21698570031.

It is an arithmetic number, because the mean of its divisors is an integer number (347177120016).

Almost surely, 2^{1345311340031} is an apocalyptic number.

1345311340031 is a deficient number, since it is larger than the sum of its proper divisors (43397140033).

1345311340031 is an equidigital number, since it uses as much as digits as its factorization.

1345311340031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43397140032.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 1345311340031 its reverse (1300431135431), we get a palindrome (2645742475462).

The spelling of 1345311340031 in words is "one trillion, three hundred forty-five billion, three hundred eleven million, three hundred forty thousand, thirty-one".