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13453531471 is a prime number
BaseRepresentation
bin11001000011110010…
…01001100101001111
31021201121012012200101
430201321021211033
5210023101001341
610102551511531
7654251062552
oct144171114517
937647165611
1013453531471
115784193356
1227356885a7
131365336c13
14918aa6699
1553b18b831
hex321e4994f

13453531471 has 2 divisors, whose sum is σ = 13453531472. Its totient is φ = 13453531470.

The previous prime is 13453531447. The next prime is 13453531499. The reversal of 13453531471 is 17413535431.

13453531471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13453531471 - 211 = 13453529423 is a prime.

It is a super-3 number, since 3×134535314713 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13453531471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13453531271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6726765735 + 6726765736.

It is an arithmetic number, because the mean of its divisors is an integer number (6726765736).

Almost surely, 213453531471 is an apocalyptic number.

13453531471 is a deficient number, since it is larger than the sum of its proper divisors (1).

13453531471 is an equidigital number, since it uses as much as digits as its factorization.

13453531471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 75600, while the sum is 37.

The spelling of 13453531471 in words is "thirteen billion, four hundred fifty-three million, five hundred thirty-one thousand, four hundred seventy-one".