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13454034300 = 22325274574673
BaseRepresentation
bin11001000011110110…
…00100010101111100
31021201122010202102200
430201323010111330
5210023213044200
610103010351500
7654255255540
oct144173042574
937648122380
1013454034300
1157844a7113
12273588b590
131365481a55
14918b97a20
1553b23a800
hex321ec457c

13454034300 has 216 divisors, whose sum is σ = 48311137056. Its totient is φ = 3067822080.

The previous prime is 13454034289. The next prime is 13454034301. The reversal of 13454034300 is 343045431.

13454034300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×134540343002 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13454034301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 2876764 + ... + 2881436.

Almost surely, 213454034300 is an apocalyptic number.

13454034300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13454034300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24155568528).

13454034300 is an abundant number, since it is smaller than the sum of its proper divisors (34857102756).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13454034300 is a wasteful number, since it uses less digits than its factorization.

13454034300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5157 (or 5147 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 27.

Adding to 13454034300 its reverse (343045431), we get a palindrome (13797079731).

The spelling of 13454034300 in words is "thirteen billion, four hundred fifty-four million, thirty-four thousand, three hundred".