Base | Representation |
---|---|
bin | 10011100101000000011… |
… | …010011011010011111011 |
3 | 11202121201121200102220221 |
4 | 103211000122123103323 |
5 | 134020342242324313 |
6 | 2510023135400511 |
7 | 166126254330325 |
oct | 23450032332373 |
9 | 4677647612827 |
10 | 1345405433083 |
11 | 4796463240a8 |
12 | 1988b9683137 |
13 | 99b42cccaca |
14 | 491919d4615 |
15 | 24ee524bc8d |
hex | 1394069b4fb |
1345405433083 has 2 divisors, whose sum is σ = 1345405433084. Its totient is φ = 1345405433082.
The previous prime is 1345405433077. The next prime is 1345405433089. The reversal of 1345405433083 is 3803345045431.
It is a balanced prime because it is at equal distance from previous prime (1345405433077) and next prime (1345405433089).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1345405433083 is a prime.
It is not a weakly prime, because it can be changed into another prime (1345405433089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672702716541 + 672702716542.
It is an arithmetic number, because the mean of its divisors is an integer number (672702716542).
Almost surely, 21345405433083 is an apocalyptic number.
1345405433083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1345405433083 is an equidigital number, since it uses as much as digits as its factorization.
1345405433083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1036800, while the sum is 43.
The spelling of 1345405433083 in words is "one trillion, three hundred forty-five billion, four hundred five million, four hundred thirty-three thousand, eighty-three".
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