Base | Representation |
---|---|
bin | 1100001111001001010011… |
… | …1000101100001010101011 |
3 | 1202122012222202211020222011 |
4 | 3003302110320230022223 |
5 | 3230413434334210021 |
6 | 44340500354140351 |
7 | 2556020655320305 |
oct | 303622470541253 |
9 | 52565882736864 |
10 | 13454335460011 |
11 | 4317a51682446 |
12 | 16136598816b7 |
13 | 76797a31cc14 |
14 | 34729c632975 |
15 | 184ea1360de1 |
hex | c3c94e2c2ab |
13454335460011 has 4 divisors (see below), whose sum is σ = 14039306566992. Its totient is φ = 12869364353032.
The previous prime is 13454335460009. The next prime is 13454335460017. The reversal of 13454335460011 is 11006453345431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13454335460011 - 21 = 13454335460009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13454335460017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 292485553456 + ... + 292485553501.
It is an arithmetic number, because the mean of its divisors is an integer number (3509826641748).
Almost surely, 213454335460011 is an apocalyptic number.
13454335460011 is a deficient number, since it is larger than the sum of its proper divisors (584971106981).
13454335460011 is an equidigital number, since it uses as much as digits as its factorization.
13454335460011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 584971106980.
The product of its (nonzero) digits is 259200, while the sum is 40.
The spelling of 13454335460011 in words is "thirteen trillion, four hundred fifty-four billion, three hundred thirty-five million, four hundred sixty thousand, eleven".
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