Base | Representation |
---|---|
bin | 11001000011111110… |
… | …01101011011111111 |
3 | 1021201201011220220111 |
4 | 30201333031123333 |
5 | 210024002321002 |
6 | 10103045530451 |
7 | 654300430321 |
oct | 144177153377 |
9 | 37651156814 |
10 | 13455120127 |
11 | 5785078999 |
12 | 2736113a27 |
13 | 1365772057 |
14 | 918d9b611 |
15 | 53b3a23d7 |
hex | 321fcd6ff |
13455120127 has 2 divisors, whose sum is σ = 13455120128. Its totient is φ = 13455120126.
The previous prime is 13455120103. The next prime is 13455120137. The reversal of 13455120127 is 72102155431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13455120127 is a prime.
It is a super-2 number, since 2×134551201272 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13455120137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6727560063 + 6727560064.
It is an arithmetic number, because the mean of its divisors is an integer number (6727560064).
Almost surely, 213455120127 is an apocalyptic number.
13455120127 is a deficient number, since it is larger than the sum of its proper divisors (1).
13455120127 is an equidigital number, since it uses as much as digits as its factorization.
13455120127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8400, while the sum is 31.
Adding to 13455120127 its reverse (72102155431), we get a palindrome (85557275558).
The spelling of 13455120127 in words is "thirteen billion, four hundred fifty-five million, one hundred twenty thousand, one hundred twenty-seven".
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