Base | Representation |
---|---|
bin | 11110100110000001001100… |
… | …001001011110000101000000 |
3 | 122122102020102111220101122222 |
4 | 132212001030021132011000 |
5 | 120114013104312000000 |
6 | 1154101132113150212 |
7 | 40225130606416406 |
oct | 3646011411360500 |
9 | 578366374811588 |
10 | 134554013000000 |
11 | 39967044582670 |
12 | 1311157685b368 |
13 | 5a10509791cc9 |
14 | 253263ddcb476 |
15 | 10850d2ebda85 |
hex | 7a604c25e140 |
134554013000000 has 196 divisors, whose sum is σ = 364093941412896. Its totient is φ = 48928728000000.
The previous prime is 134554012999997. The next prime is 134554013000027. The reversal of 134554013000000 is 310455431.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 4883909 + ... + 17116091.
Almost surely, 2134554013000000 is an apocalyptic number.
134554013000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 134554013000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (182046970706448).
134554013000000 is an abundant number, since it is smaller than the sum of its proper divisors (229539928412896).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134554013000000 is an frugal number, since it uses more digits than its factorization.
134554013000000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12232236 (or 12232201 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 26.
Adding to 134554013000000 its reverse (310455431), we get a palindrome (134554323455431).
The spelling of 134554013000000 in words is "one hundred thirty-four trillion, five hundred fifty-four billion, thirteen million", and thus it is an aban number.
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