Base | Representation |
---|---|
bin | 111110101100010010… |
… | …0110100110001100111 |
3 | 110212111121011100222101 |
4 | 1331120210310301213 |
5 | 4201210242101120 |
6 | 141503112512531 |
7 | 12504154261213 |
oct | 1753044646147 |
9 | 425447140871 |
10 | 134630034535 |
11 | 52107165657 |
12 | 221133ab747 |
13 | c9071a9739 |
14 | 6732383943 |
15 | 377e58a90a |
hex | 1f58934c67 |
134630034535 has 4 divisors (see below), whose sum is σ = 161556041448. Its totient is φ = 107704027624.
The previous prime is 134630034533. The next prime is 134630034541. The reversal of 134630034535 is 535430036431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 535430036431 = 151 ⋅3545894281.
It is a cyclic number.
It is not a de Polignac number, because 134630034535 - 21 = 134630034533 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 134630034494 and 134630034503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134630034533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13463003449 + ... + 13463003458.
It is an arithmetic number, because the mean of its divisors is an integer number (40389010362).
Almost surely, 2134630034535 is an apocalyptic number.
134630034535 is a deficient number, since it is larger than the sum of its proper divisors (26926006913).
134630034535 is an equidigital number, since it uses as much as digits as its factorization.
134630034535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26926006912.
The product of its (nonzero) digits is 194400, while the sum is 37.
The spelling of 134630034535 in words is "one hundred thirty-four billion, six hundred thirty million, thirty-four thousand, five hundred thirty-five".
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