1346444631141 has 4 divisors (see below), whose sum is σ = 1795259508192. Its totient is φ = 897629754092.

The previous prime is 1346444631131. The next prime is 1346444631173. The reversal of 1346444631141 is 1411364446431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1346444631141 - 2¹¹ = 1346444629093 is a prime.

It is a super-3 number, since 3×1346444631141³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1346444631093 and 1346444631102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1346444631131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224407438521 + ... + 224407438526.

It is an arithmetic number, because the mean of its divisors is an integer number (448814877048).

Almost surely, 2^{1346444631141} is an apocalyptic number.

It is an amenable number.

1346444631141 is a deficient number, since it is larger than the sum of its proper divisors (448814877051).

1346444631141 is an equidigital number, since it uses as much as digits as its factorization.

1346444631141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 448814877050.

The product of its digits is 331776, while the sum is 42.

The spelling of 1346444631141 in words is "one trillion, three hundred forty-six billion, four hundred forty-four million, six hundred thirty-one thousand, one hundred forty-one".