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13474808074151 is a prime number
BaseRepresentation
bin1100010000010101100100…
…1001100000111110100111
31202201011211112122210221022
43010011121021200332213
53231232401331333101
644354124045241355
72560344206551064
oct304053111407647
952634745583838
1013474808074151
1143256a7963466
121617611b6325b
137698908b1798
143482815c1c6b
1518579d835a1b
hexc4159260fa7

13474808074151 has 2 divisors, whose sum is σ = 13474808074152. Its totient is φ = 13474808074150.

The previous prime is 13474808074129. The next prime is 13474808074153. The reversal of 13474808074151 is 15147080847431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13474808074151 - 210 = 13474808073127 is a prime.

Together with 13474808074153, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13474808074093 and 13474808074102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13474808074153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6737404037075 + 6737404037076.

It is an arithmetic number, because the mean of its divisors is an integer number (6737404037076).

Almost surely, 213474808074151 is an apocalyptic number.

13474808074151 is a deficient number, since it is larger than the sum of its proper divisors (1).

13474808074151 is an equidigital number, since it uses as much as digits as its factorization.

13474808074151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3010560, while the sum is 53.

The spelling of 13474808074151 in words is "thirteen trillion, four hundred seventy-four billion, eight hundred eight million, seventy-four thousand, one hundred fifty-one".