Base | Representation |
---|---|
bin | 1100010000010101100100… |
… | …1001100000111110100111 |
3 | 1202201011211112122210221022 |
4 | 3010011121021200332213 |
5 | 3231232401331333101 |
6 | 44354124045241355 |
7 | 2560344206551064 |
oct | 304053111407647 |
9 | 52634745583838 |
10 | 13474808074151 |
11 | 43256a7963466 |
12 | 1617611b6325b |
13 | 7698908b1798 |
14 | 3482815c1c6b |
15 | 18579d835a1b |
hex | c4159260fa7 |
13474808074151 has 2 divisors, whose sum is σ = 13474808074152. Its totient is φ = 13474808074150.
The previous prime is 13474808074129. The next prime is 13474808074153. The reversal of 13474808074151 is 15147080847431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13474808074151 - 210 = 13474808073127 is a prime.
Together with 13474808074153, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13474808074093 and 13474808074102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13474808074153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6737404037075 + 6737404037076.
It is an arithmetic number, because the mean of its divisors is an integer number (6737404037076).
Almost surely, 213474808074151 is an apocalyptic number.
13474808074151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13474808074151 is an equidigital number, since it uses as much as digits as its factorization.
13474808074151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3010560, while the sum is 53.
The spelling of 13474808074151 in words is "thirteen trillion, four hundred seventy-four billion, eight hundred eight million, seventy-four thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •