Base | Representation |
---|---|
bin | 11001001000000010… |
… | …00000101101001101 |
3 | 1021211002012122120222 |
4 | 30210001000231031 |
5 | 210111210143301 |
6 | 10110303121125 |
7 | 655162566212 |
oct | 144401005515 |
9 | 37732178528 |
10 | 13489146701 |
11 | 57a22a9628 |
12 | 27455a31a5 |
13 | 136c826a14 |
14 | 91d6d7b09 |
15 | 53e37431b |
hex | 324040b4d |
13489146701 has 2 divisors, whose sum is σ = 13489146702. Its totient is φ = 13489146700.
The previous prime is 13489146661. The next prime is 13489146703. The reversal of 13489146701 is 10764198431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8963355625 + 4525791076 = 94675^2 + 67274^2 .
It is a cyclic number.
It is not a de Polignac number, because 13489146701 - 230 = 12415404877 is a prime.
It is a super-3 number, since 3×134891467013 (a number of 31 digits) contains 333 as substring.
Together with 13489146703, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13489146703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6744573350 + 6744573351.
It is an arithmetic number, because the mean of its divisors is an integer number (6744573351).
Almost surely, 213489146701 is an apocalyptic number.
It is an amenable number.
13489146701 is a deficient number, since it is larger than the sum of its proper divisors (1).
13489146701 is an equidigital number, since it uses as much as digits as its factorization.
13489146701 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 44.
The spelling of 13489146701 in words is "thirteen billion, four hundred eighty-nine million, one hundred forty-six thousand, seven hundred one".
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