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134902541 is a prime number
BaseRepresentation
bin10000000101001…
…11001100001101
3100101211202111102
420002213030031
5234013340131
621215232445
73225436604
oct1002471415
9311752442
10134902541
116a170304
1239218725
1321c440b7
1413cb8a3b
15bc9b1cb
hex80a730d

134902541 has 2 divisors, whose sum is σ = 134902542. Its totient is φ = 134902540.

The previous prime is 134902517. The next prime is 134902553. The reversal of 134902541 is 145209431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120538441 + 14364100 = 10979^2 + 3790^2 .

It is an emirp because it is prime and its reverse (145209431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134902541 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134902501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67451270 + 67451271.

It is an arithmetic number, because the mean of its divisors is an integer number (67451271).

Almost surely, 2134902541 is an apocalyptic number.

It is an amenable number.

134902541 is a deficient number, since it is larger than the sum of its proper divisors (1).

134902541 is an equidigital number, since it uses as much as digits as its factorization.

134902541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

The square root of 134902541 is about 11614.7553138239. The cubic root of 134902541 is about 512.8693079548.

The spelling of 134902541 in words is "one hundred thirty-four million, nine hundred two thousand, five hundred forty-one".