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134904853 is a prime number
BaseRepresentation
bin10000000101001…
…11110000010101
3100101211212200001
420002213300111
5234013423403
621215251301
73225446416
oct1002476025
9311755601
10134904853
116a172016
1239219b31
1321c45175
1413cb980d
15bc9bc1d
hex80a7c15

134904853 has 2 divisors, whose sum is σ = 134904854. Its totient is φ = 134904852.

The previous prime is 134904793. The next prime is 134904863. The reversal of 134904853 is 358409431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134142724 + 762129 = 11582^2 + 873^2 .

It is an emirp because it is prime and its reverse (358409431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134904853 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134904863) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67452426 + 67452427.

It is an arithmetic number, because the mean of its divisors is an integer number (67452427).

Almost surely, 2134904853 is an apocalyptic number.

It is an amenable number.

134904853 is a deficient number, since it is larger than the sum of its proper divisors (1).

134904853 is an equidigital number, since it uses as much as digits as its factorization.

134904853 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 37.

The square root of 134904853 is about 11614.8548419685. The cubic root of 134904853 is about 512.8722378405.

The spelling of 134904853 in words is "one hundred thirty-four million, nine hundred four thousand, eight hundred fifty-three".