Base | Representation |
---|---|
bin | 10011101000011110100… |
… | …100110100000110000111 |
3 | 11202222100101012010011101 |
4 | 103220132210310012013 |
5 | 134101010432313431 |
6 | 2511441043520531 |
7 | 166320523502011 |
oct | 23503644640607 |
9 | 4688311163141 |
10 | 1349132697991 |
11 | 480189266421 |
12 | 199579989147 |
13 | 9a2b827b7c0 |
14 | 49426a311b1 |
15 | 2516259b961 |
hex | 13a1e934187 |
1349132697991 has 4 divisors (see below), whose sum is σ = 1452912136312. Its totient is φ = 1245353259672.
The previous prime is 1349132697971. The next prime is 1349132698019. The reversal of 1349132697991 is 1997962319431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1349132697991 - 217 = 1349132566919 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1349132697971) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51889719141 + ... + 51889719166.
It is an arithmetic number, because the mean of its divisors is an integer number (363228034078).
Almost surely, 21349132697991 is an apocalyptic number.
1349132697991 is a deficient number, since it is larger than the sum of its proper divisors (103779438321).
1349132697991 is a wasteful number, since it uses less digits than its factorization.
1349132697991 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103779438320.
The product of its digits is 19840464, while the sum is 64.
The spelling of 1349132697991 in words is "one trillion, three hundred forty-nine billion, one hundred thirty-two million, six hundred ninety-seven thousand, nine hundred ninety-one".
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