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134917639 = 521258959
BaseRepresentation
bin10000000101010…
…10111000000111
3100101212112012121
420002222320013
5234014331024
621215430411
73225531613
oct1002527007
9311775177
10134917639
116a18068a
1239225407
1321c4ac2c
1413cc0343
15bca08e4
hex80aae07

134917639 has 4 divisors (see below), whose sum is σ = 135177120. Its totient is φ = 134658160.

The previous prime is 134917637. The next prime is 134917649. The reversal of 134917639 is 936719431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134917639 - 21 = 134917637 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134917595 and 134917604.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134917633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 128959 + ... + 130000.

It is an arithmetic number, because the mean of its divisors is an integer number (33794280).

Almost surely, 2134917639 is an apocalyptic number.

134917639 is a deficient number, since it is larger than the sum of its proper divisors (259481).

134917639 is an equidigital number, since it uses as much as digits as its factorization.

134917639 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 259480.

The product of its digits is 122472, while the sum is 43.

The square root of 134917639 is about 11615.4052447601. The cubic root of 134917639 is about 512.8884403149. Note that the first 3 decimals are identical.

The spelling of 134917639 in words is "one hundred thirty-four million, nine hundred seventeen thousand, six hundred thirty-nine".

Divisors: 1 521 258959 134917639