Base | Representation |
---|---|
bin | 1100010001010111001011… |
… | …1000000001001111001101 |
3 | 1202202212021220210012220101 |
4 | 3010111302320001033031 |
5 | 3232024433402030433 |
6 | 44410155412451101 |
7 | 2561536510006012 |
oct | 304256270011715 |
9 | 52685256705811 |
10 | 13492419564493 |
11 | 4332115108861 |
12 | 161ab08019a91 |
13 | 76b43949479c |
14 | 349072599709 |
15 | 185e7ea4a07d |
hex | c4572e013cd |
13492419564493 has 2 divisors, whose sum is σ = 13492419564494. Its totient is φ = 13492419564492.
The previous prime is 13492419564469. The next prime is 13492419564497. The reversal of 13492419564493 is 39446591429431.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10397026211364 + 3095393353129 = 3224442^2 + 1759373^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13492419564493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13492419564497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6746209782246 + 6746209782247.
It is an arithmetic number, because the mean of its divisors is an integer number (6746209782247).
Almost surely, 213492419564493 is an apocalyptic number.
It is an amenable number.
13492419564493 is a deficient number, since it is larger than the sum of its proper divisors (1).
13492419564493 is an equidigital number, since it uses as much as digits as its factorization.
13492419564493 is an evil number, because the sum of its binary digits is even.
The product of its digits is 100776960, while the sum is 64.
The spelling of 13492419564493 in words is "thirteen trillion, four hundred ninety-two billion, four hundred nineteen million, five hundred sixty-four thousand, four hundred ninety-three".
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