134935 has 4 divisors (see below), whose sum is σ = 161928. Its totient is φ = 107944.

The previous prime is 134923. The next prime is 134947. The reversal of 134935 is 539431.

134935 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 539431 = 31 ⋅17401.

It is an interprime number because it is at equal distance from previous prime (134923) and next prime (134947).

It is a cyclic number.

It is not a de Polignac number, because 134935 - 2⁷ = 134807 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13489 + ... + 13498.

It is an arithmetic number, because the mean of its divisors is an integer number (40482).

2¹³⁴⁹³⁵ is an apocalyptic number.

134935 is a deficient number, since it is larger than the sum of its proper divisors (26993).

134935 is an equidigital number, since it uses as much as digits as its factorization.

134935 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26992.

The product of its digits is 1620, while the sum is 25.

The square root of 134935 is about 367.3349969714. The cubic root of 134935 is about 51.2910438610.

Subtracting 134935 from its reverse (539431), we obtain a square (404496 = 636²).

The spelling of 134935 in words is "one hundred thirty-four thousand, nine hundred thirty-five".